MCQ
Area under the curve $y = \sqrt {3x + 4} $ between $x = 0$ and $x = 4,$ is
- A$\frac{{56}}{9}$ sq. unit
- B$\frac{{64}}{9}$ sq. unit
- C$8$ sq. unit
- ✓None of these
✓
Answer
Correct option: D.
None of these
d
(d) Area $ = \int_0^4 {\sqrt {3x + 4} } dx $
(d) Area $ = \int_0^4 {\sqrt {3x + 4} } dx $
$= \left| {\frac{{{{(3x + 4)}^{3/2}}}}{{3.(3/2)}}} \right|_0^4$
$ = \frac{2}{9} \times 56 = \frac{{112}}{9}\,\, sq. \,unit$
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