Question
$arg\left( {\frac{{3 + i}}{{2 - i}} + \frac{{3 - i}}{{2 + i}}} \right)$ is equal to

Answer

c
(c) $arg\left( {\frac{{3 + i}}{{2 - i}} + \frac{{3 - i}}{{2 + i}}} \right) = arg\left( {\frac{{6 + 5i + {i^2} + 6 - 5i + {i^2}}}{5}} \right)$
$ = arg\left( {\frac{{10}}{5}} \right) = 0$.

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