MCQ
Arrange the bonds in order of increasing ionic character in the molecules. $\mathrm{LiF}, \mathrm{K}_2 \mathrm{O}, \mathrm{N}_2, \mathrm{SO}_2$ and $\mathrm{CIF}_3$.
  • A
    $\mathrm{CIF}_3<\mathrm{N}_2<\mathrm{SO}_2<\mathrm{K}_2 \mathrm{O}<\mathrm{LiF}$
  • B
    $\mathrm{LiF}<\mathrm{K}_2 \mathrm{O}<\mathrm{CIF}_3<\mathrm{SO}_2<\mathrm{N}_2$
  • $\mathrm{N}_2<\mathrm{SO}_2<\mathrm{CIF}_3<\mathrm{K}_2 \mathrm{O}<\mathrm{LiF}$
  • D
    $\mathrm{N}_2<\mathrm{CIF}_3<\mathrm{SO}_2<\mathrm{K}_2 \mathrm{O}<\mathrm{LiF}$

Answer

Correct option: C.
$\mathrm{N}_2<\mathrm{SO}_2<\mathrm{CIF}_3<\mathrm{K}_2 \mathrm{O}<\mathrm{LiF}$
c
Increasing order of ionic character

$\mathrm{N}_2<\mathrm{SO}_2<\mathrm{ClF}_3<\mathrm{K}_2 \mathrm{O}<\mathrm{LiF}$

Ionic character depends upon difference of electronegativity (bond polarity).

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