Question
Arrange the following:
H–H, D–D and F–F in order of increasing bond dissociation enthalpy.

Answer

Due to lone pairs of F, bond pairs experience repulsion, hence, F-F has low bond dissociation energy. In D-D, due to higher nuclear attraction bond dissociation energy is geater than H- H. Increasing bond dissociation enthalpy, F-F < H-H < D-D.

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