MCQ
As a result of $sp$ hybridization, we get
- ATwo mutual perpendicular orbitals
- ✓Two orbitals at ${180^o}$
- CFour orbitals in tetrahedral directions
- DThree orbitals in the same plane
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Major product $(A)$ of the above reaction
Given : $K_f (H_2O)$ = $2\ K\ kg\ mole^{-1}$, $K_{sp} (PbCl_2)$ = $4 × 10^{-6}$
(Assume molarity to be equal to molality) .....$^oC$