- ✓Increases
- BDecreases
- CBecomes zero
- DDoes not change
|
$Hybridization$ |
$s\%$ |
$Angle$ |
|
$sp$ |
$50$ |
$180^o$ |
|
$s{p^2}$ |
$33.3$ |
$120^o$ |
|
$s{p^3}$ |
$25$ |
$109.28^o$ |
|
$s{p^3}{d^1}$ |
$20$ |
$90^o$ $and$ $120^o$ |
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$\begin{array}{*{20}{c}}
{C{H_3}\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{{H_3}C - C - CH = C{H_2}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_3}\,\,\,\,\,\,\,\,\,}
\end{array}$ $\xrightarrow{{{H_2}O/{H^ \oplus }}}{\mkern 1mu} \mathop A\limits_{Major\,product} \, + \,\mathop B\limits_{Minor\,product} $
major product:
$Ca_3(PO_4)_2 + SiO_2 + C + O_2 + H_2O \to CaSiO_3 + CO_2 + H_3PO_4$
If $1.0\ kg$ each of calcium phosphate and silica are used with excess of $C$ , $O_2$ and $H_2O$ , what is maximum quantity of phosphoric acid that can be produced. $(Ca = 40, P = 31, Si = 28)$
