MCQ
As the $s-$character of hybridisation orbital increases, the bond angle
  • Increases
  • B
    Decreases
  • C
    Becomes zero
  • D
    Does not change

Answer

Correct option: A.
Increases
(a) $s-$character increases with increase in bond angle.

$Hybridization$

$s\%$

$Angle$

$sp$

$50$

$180^o$

$s{p^2}$

$33.3$

$120^o$

$s{p^3}$

$25$

$109.28^o$

$s{p^3}{d^1}$

$20$

$90^o$ $and$ $120^o$

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