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Statement $I$ : The correct order of first ionization enthalpy values of $\mathrm{Li}, \mathrm{Na}, \mathrm{F}$ and $\mathrm{Cl}$ is $\mathrm{Na}<\mathrm{Li}<\mathrm{Cl}<\mathrm{F}$.
Statement $II$ : The correct order of negative electron gain enthalpy values of $\mathrm{Li}, \mathrm{Na}, \mathrm{F}$ and $\mathrm{Cl}$ is $\mathrm{Na}<\mathrm{Li}<\mathrm{F}<\mathrm{Cl}$
In the light of the above statements, choose the correct answer from the options given below :
$A.6{H_2}{O_{\left( s \right)}} \rightleftharpoons A.2{H_2}{O_{(s)}} + \mathop {4{H_2}{O_{(g)}}};{{K_P} = 1.6 \times {{10}^{ - 11}}} $
$B.12{H_2}{O_{\left( s \right)}} \rightleftharpoons B.7{H_2}{O_{(s)}} + \mathop {5{H_2}{O_{(g)}}};{{K_P} = 2.43 \times {{10}^{ - 13}}} $
$B.10{H_2}{O_{\left( s \right)}} \rightleftharpoons {C_{(s)}} + \mathop {10{H_2}{O_{(g)}}};{{K_P} = {{10}^{ - 30}}} $
Aqueous tension of $H_2O$ at $0\,^oC$ is given as $0.76\ torr$
$(I)$ The most effective drying agent will be $C_{(s)}$. Out of $C_{(s)}$ , $B. 7H_2O_{(s)}$ & $A. 2H_2O_{(s)}$
$(II)$ At $0\,^oC$, $A.6H_2O_{(s)}$ & $B.12H_2O_{(s)}$ will
$(III)$ If $R.H$ is less than $100\%$ in a chamber at $0\,^oC$, then none of the substance can act as deliquescent
(image)
($A$) $R$ is steam volatile
($B$) $Q$ gives dark violet coloration with $1 \%$ aqueous $FeCl_3$ solution
($C$) $S$ gives yellow precipitate with $2, 4$-dinitrophenylhydrazine
($D$) $S$ gives dark violet coloration with $1 \%$ aqueous $FeCl_3$ solution
[Kinetic $:$ Potential ] and [Total $:$ Kinetic]