Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$(K_a \,\,of\,\, HA = 4 \times 10^{-7} ,\, log\,2 = 0.3)$
Assertion $(A)$ : $\mathrm{NH}_3$ and $\mathrm{NF}_3$ molecule have pyramidal shape with a lone pair of electrons on nitrogen atom. The resultant dipole moment of $\mathrm{NH}_3$ is greater than that of $\mathrm{NF}_3$.
Reason $(R)$ : In $\mathrm{NH}_3$, the orbital dipole due to lone pair is in the same direction as the resultant dipole moment of the $\mathrm{N}-\mathrm{H}$ bonds. $\mathrm{F}$ is the most electronegative element.
In the light of the above statements, choose the correct answer from the options given below:
A for disproportionation reaction.
B for comproportionation reaction.
C for either intermolecular redox reaction or displacement reaction.
D for either thermal combination redox reaction or thermal decomposition redox reaction.
$MnO_4^ - + {H^ + } + B{r^ - } \longrightarrow M{n^{2 + }}\left( {aq.} \right) + B{r_2} \uparrow $
$(A)$ $m-CH_3OPhCH_2^+$ $(B)$ $p-CH_3OPhCH_2^+$ $(C)$ $PhCH_2^+$ $(D)$ $p-NO_2PhCH_2^+$