Download App

4. Chemical bonding and molecular structure — Chemistry STD 11 Science — Question

Rajasthan BoardEnglish MediumSTD 11 ScienceChemistry4. Chemical bonding and molecular structure1 Mark
MCQ
Assertion : Sigma $(\sigma )$ is a strong bond, while pi $(\pi )$ is a weak bond.
Reason : Atoms rotate freely about pi $(\pi )$ bond.
  • A
    If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
  • B
    If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
  • ✓
    If the Assertion is correct but Reason is incorrect.
  • D
    If both the Assertion and Reason are incorrect.
✓

Answer

Correct option: C.
If the Assertion is correct but Reason is incorrect.
c
Sigma $(\sigma )$ bond is formed by axial overlap of atomic orbitals while pi $(\pi )$ bond is formed by lateral overlap. Since axial overlapping takes place to a greater extent than the lateral overlapping, former $(\sigma )$ bond is stronger than pi bond. Atoms attached to doubly bonded atom can't rotate freely around the double bond.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 4. Chemical bonding and molecular structure→4. Chemical bonding and molecular structure — all question types→Chemistry STD 11 Science question papers→Rajasthan Board STD 11 Science question papers→Rajasthan Board question paper generator→

Similar questions

Going from fluorine to chlorine, bromine and iodine, the electronegativity
→
When $2-$ butyne is treated with $H_2/$ Lindlar's catalyst, compound $X$ is produced as the major product and when treated with $Na/liq.$ $NH_3$ it produces $Y$ as the major product. Which of the following statements is correct?
→
The colour of an electrolyte solution depends on
→
Which of the following molecules has the maximum dipole moment ?
→
Propene is allowed to react with B2​ D6​ and the product is treated with acetic acid. The final product obtained is:
→
Borax has the molecular formula
→
 In the equilibrium reaction, N2​ + 3H2 ​⇔ 2NH3​, the sign of ΔH accompanying the reaction is:
→
Which is not a electrophile
→
The dissociation constant of an acid $HA$  is $1 \times {10^{ - 5}}$. The $pH$ of $0.1$ molar solution of the acid will be
→
Which of the order for ionisation energy is correct
→