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Motion in Two Dimension — JEE physics STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 ScienceJEE physicsMotion in Two Dimension1 Mark
Question
Assertion : When an automobile while going too fast around a curve overturns, its inner wheels leave the ground first.
Reason : For a safe turn the velocity of automobile should be less than the value of safe limit velocity.
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Answer

(b) When automobile moves in circular path then reaction on inner wheel and outer wheel will be different.$R_{\text {inner }}=\frac{M}{2}\left[g-\frac{v^2 h}{r a}\right]$ and $R_{\text {outer }}=\frac{M}{2}\left[g+\frac{v^2 h}{r a}\right]$ In critical condition $v_{\text {safe }}=\sqrt{\frac{g r a}{h}}$If $v$ is equal or more that thus critical value then reaction on inner wheel becomes zero. So it leaves the ground first.

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