MCQ
Assuming $2 s-2 p$ mixing is $NOT$ operative, the paramagnetic species among the following is :
  • A
    $Be _2$
  • B
    $B_2$
  • $C _2$
  • D
    $N _2$

Answer

Correct option: C.
$C _2$
c
If $2 s-2 p$ mixing is not operative, the increasing order of Molecular orbitals will be :

$\sigma 1 s^2, \sigma^* 1 s^2, \sigma 2 s^2, \sigma^* 2 s^2, \sigma 2 P_x^2\left[\begin{array}{l}\pi 2 p_y^1 \\ \pi 2 p_z^1\end{array}\right]$

Considering this $Be _2$ and $B _2$ become diamagnetic, so does $N _2$. Only $C _2$ would be paramagnatic with electronic configuration as above

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