MCQ
Assuming complete dissociation, the $pH$ of a $0.01 \,M$ $NaOH$ solution is equal to
- A$2$
- B$14$
- ✓$12$
- D$0.01$
✓
Answer
Correct option: C.
$12$
(c) ${10^{ - 2}}\,M\,NaOH$ will give $[O{H^ - }] = {10^{ - 2}}$
$\therefore \,pOH = 2$, Also $pH + pOH = 14$
$\therefore \,pH = 12$.
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