Assuming that Ba(OH)_ 2 is completely ionised in aqueous solution… - Vidyadip

MCQ

Assuming that $\mathrm{Ba}(\mathrm{OH})_{2}$ is completely ionised in aqueous solution under the given conditions the concentration of $\mathrm{H}_{3} \mathrm{O}^{+}$ions in $0.005 \,\mathrm{M}$ aqueous solution of $\mathrm{Ba}(\mathrm{OH})_{2}$ at $298\, \mathrm{~K}$ is $.....\times 10^{-12}$ $mol$ $\mathrm{L}^{-1}$. (Nearest integer)

A
$2$
✓
$1$
C
$3$
D
$4$

✓

Answer

Correct option: B.

$1$

b
$\mathrm{Ba}(\mathrm{OH})_{2} \rightarrow \mathrm{Ba}^{+2}+2 \mathrm{OH}^{-} \rightarrow 2 \times 0.005=0.01=10^{-2}$

At $298\, \mathrm{~K}:$ in aq. solution $[H3O^{+}][\mathrm{OH}^{-}]=10^{-14}$

${\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]=\frac{10^{-14}}{10^{-2}}=10^{-12}}$

${\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]=1 \times 10^{-12}\, \mathrm{M}}$

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