- A$113$
- ✓$120$
- C$119$
- D$106$
hence the alkaline earth metal shall belong to the second group, thus its atomic number would be : $120\{$ Option $B\}$
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What is $A$
$Xe{F_6}\xrightarrow{{ + {H_2}O}}A\xrightarrow{{ + {H_2}O}}B\xrightarrow{{ + {H_2}O}}C$
$(I)$ $\begin{array}{*{20}{c}}
{{{(C{H_3})}_3}Si - NB{H_2}} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Si{{(C{H_3})}_3}}
\end{array}$ $(II)$ $\begin{array}{*{20}{c}}
{{{(C{H_3})}_3}C - NB{H_2}} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{{(C{H_3})}_3}}
\end{array}$

${C_6{H_5}N{H_2}}\xrightarrow{{{{(Ac)}_2}O}}$$X\xrightarrow{{B{r_2}/CC{l_4}}}Y\xrightarrow{{HOH}}Z$
$[A]$ $\mathrm{Cr}_2 \mathrm{O}_3, \mathrm{BeO}, \mathrm{SnO}, \mathrm{SnO}_2$
$[B]$ $\mathrm{Cr}_2 \mathrm{O}_3, \mathrm{CrO}, \mathrm{SnO}, \mathrm{PbO}$
$[C]$ $\mathrm{NO}, \mathrm{B}_2 \mathrm{O}_3, \mathrm{PbO}, \mathrm{SnO}_2$
$[D]$ $\mathrm{ZnO}, \mathrm{Al}_2 \mathrm{O}_3, \mathrm{PbO}, \mathrm{PbO}_2$