Question
At 1atm will the $\Delta_\text{f}\text{H}^\circ$ be zero for Cl2(g) and Br2(g)? Explain.

Answer

$\Delta_\text{f}\text{H}^\circ$ for Cl2(g) will be zero but $\Delta_\text{f}\text{H}^\circ$ for Br2(g) will not be zero because liquid bromine is its elementary state and not gaseous bromine.

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