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6.2. Equilibrium - II (icon Equilibrium) — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistry6.2. Equilibrium - II (icon Equilibrium)1 Mark
MCQ
At ${20\,^o}C,$ the $A{g^ + }$ ion concentration in a saturated solution of $A{g_2}Cr{O_4}$ is $1.5 \times {10^{ - 4}}\,mole/litre.$ At ${20\,^o}C,$the solubility product of $A{g_2}Cr{O_4}$ would be
  • A
    $3.3750 \times {10^{ - 12}}$
  • B
    $1.6875 \times {10^{ - 10}}$
  • ✓
    $1.6875 \times {10^{ - 12}}$
  • D
    $1.6875 \times {10^{ - 11}}$
✓

Answer

Correct option: C.
$1.6875 \times {10^{ - 12}}$
(c) $AgCr{O_4} ⇌ \mathop {2A{g^ + }}\limits_{{{(2S)}^2}} + \mathop {CrO_4^ - }\limits_{S\,\,\,} $

${K_{sp}} = 4{S^3}$ given $2S = 1.5 \times {10^{ - 4}}$

$\therefore \,{K_{sp}} = {(2S)^2} \times S$

$ = {(1.5 \times {10^{ - 4}})^2} \times \left( {\frac{{1.5 \times {{10}^{ - 4}}}}{2}} \right)$ $ = 1.6875 \times {10^{ - 12}}$

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