Concentration of ${H_3}{O^ + }$ in distilled water$ = 1 \times {10^{ - 6}}$ $mol/l$.
Now $[{H_3}{O^ + }] = [O{H^ - }]$
${K_w} = [1 \times {10^{ - 6}}] \times [1 \times {10^{ - 6}}] = 1 \times {10^{ - 12}}$.
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$\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}\,} \\
{\,\,\,\,||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,} \\
{C{H_3} - C - C{H_2} - C - CN} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}}
\end{array}$
