MCQ
At a place where the acceleration due to gravity is $10\,m\,{\sec ^{ - 2}}$ a force of $5\, kg-wt$ acts on a body of mass $10\, kg$ initially at rest. The velocity of the body after $4$ second is .......... $m/\sec^{-1}$
  • A
    $5$
  • B
    $10$
  • $20$
  • D
    $50$

Answer

Correct option: C.
$20$
c
(c) Acceleration $ = \frac{{{\rm{Force}}}}{{{\rm{Mass}}}} = \frac{{50\;N}}{{10\;kg}} = 5\;m/{s^2}$

From $v = u + at = 0 + 5 \times 4 = 20\;m/s$

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