Osmotic pressure ($p$) of a solution at a constant temperature is directly proportional to its concentration $C$ (i.e., moles per litre) $C =\frac{ n }{ V }$
where $n$ is the number of moles of solute present in volume $V$ litres of solution.So osmatic pressure depends on molar mass.
Hence option $A$ and $B$ are correct, remaining does not make any sense so wrong options.
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| Experiment | $\frac{[ X ]}{ mol \;L ^{-1}}$ | $\frac{[ Y ]}{ mol\; L ^{-1}}$ | $\frac{\text { Initial rate }}{ mol\; L ^{-1}\; min ^{-1}}$ |
| $I$ | $0.1$ | $0.1$ | $2 \times 10^{-3}$ |
| $II$ | $0.2$ | $0.2$ | $4 \times 10^{-3}$ |
| $III$ | $0.4$ | $0.4$ | $M \times 10^{-3}$ |
| $IV$ | $0.1$ | $0.2$ | $2 \times 10^{-3}$ |
Examine the data of table and calculate ratio of numerical value of $M$
(1)The rate of reaction is independent of the concentration of the nucleophile
(2)The nucleophile attacks the ${C^ - }$ atom on the side of the molecule opposite to the group being displaced
(3)The reaction proceeds with simultaneous bond formation and bond rupture/ cleavage
Amongst the following which of the above were true
image$\mathop {\xrightarrow{{NaN{O_2}}}}\limits_{HCl} A\,\,\xrightarrow{{CuCN}}B\,\,\mathop {\xrightarrow{{{H_2}}}}\limits_{Ni} C\,\,\xrightarrow{{HN{O_2}}}D$
${image}$