At what distance for a long straight wire carrying a current of $12\, A$ will the magnetic field be equal to $3 \times 10^{-5} Wb / m ^{2}$ ?
A$8 \times 10^{-2} m$
B$12 \times 10^{-2} m$
C$18 \times 10^{-2} m$
D$24 \times 10^{-2} m$
AIIMS 2019, Medium
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A$8 \times 10^{-2} m$
a The magnetic field is calculated as,
$B=\frac{\mu_{0} I}{2 \pi r}$
The radius is calculated as,
$r=\frac{\mu_{0} I}{2 \pi B}$
$=\frac{\left(4 \pi \times 10^{-7}\right)(12 A )}{2 \pi\left(3 \times 10^{-5} Wb / m ^{2}\right)}$
$=8 \times 10^{-2} m$
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