Question
At which place on the Earth surface the gravitational acceleration minimum? Why?

Answer

  1. Gravitational acceleration on the surface of the Earth depends on latitude of the place as well as rotation and shape of the Earth.
  2. At equator, latitude $\theta = 0^\circ.$
    $\therefore g’ = g – Rω^2$
    i.e., the acceleration due to gravity ¡s reduced by amount $Rω^2(≈ 0.034 m/s^2)$ at equator.
    Also, shape of the Earth is actually an ellipsoid, bulged at equator. The equatorial radius of the Earth is $6378 km$, which is maximum. As $g \propto \frac{1}{ R ^2}$ acceleration due to gravity is minimum on equator i.e., $9.7804 m / s ^2$.

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