(Because $v,$ $\gamma$-constant).
Hence $\frac{{{T_{{H_2}}}}}{{{T_{{O_2}}}}} = \frac{{{M_{{H_2}}}}}{{{M_{{O_2}}}}}$
==> $\frac{{{T_{{H_2}}}}}{{(273 + 100)}} = \frac{2}{{32}}$
==> ${T_{{H_2}}} = 23.2K = - 249.7^\circ C$
If the distances are expressed in cms and time in seconds, then the wave velocity will be ...... $cm/sec$