MCQ
Atomic radius of fcc is
- A$\frac{a}{2}$
- ✓$\frac{a}{2 \sqrt{2}}$
- C$\frac{\sqrt{3}}{4} a$
- D$\frac{\sqrt{3}}{2} a$
✓
Answer
Correct option: B.
$\frac{a}{2 \sqrt{2}}$
$\frac{a}{2 \sqrt{2}}$
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