MCQ
$A\xrightarrow{{}}{(C{H_3})_2}C = CHCOC{H_3}\,\,\,\,A$ is
- ✓Acetone
- BAcetaldehyde
- CPropionaldehyde
- DFormaldehyde
✓
Answer
Correct option: A.
Acetone
a
(a)Two molecules of acetone condense in presence of dry $HCl$ gas to form mesityl oxide.
(a)Two molecules of acetone condense in presence of dry $HCl$ gas to form mesityl oxide.
$\begin{array}{*{20}{c}}
{C{H_3}} \\
{C{H_3}}
\end{array} > C = O\, + \,$ $\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,\,\,\,\,\,\,O} \\
{\,\,\,\,\,\,\,\,\,\,\,\,||} \\
{{H_2} - CH - C - C{H_3}}
\end{array}$ $\xrightarrow[{ - \,{H_2}O}]{{HCl}}$ $\mathop {{{(C{H_3})}_2}C = CH.COC{H_3}}\limits_{Mesityl\,\,oxide} $
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