MCQ
Azimuthal quantum number for last electron of $Na$ atom is
  • A
    $1$
  • B
    $2$
  • C
    $3$
  • $0$

Answer

Correct option: D.
$0$
d
(d) $N{a_{11}} = 1{s^2}2{s^2}{p^6}3{s^2}$

$n = 3,\,l = 0,\,m = 0$ and $s = + \frac{1}{2}.$

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