Question
Balance the following equations : $Fe + \ce{H_2 O \rightleftharpoons Fe_3O_4}+ H _2$

Answer

$Fe + \ce{H_2O \rightleftharpoons Fe_3O_4}+ H_2$
To make $\ce{Fe 3}$ mutliply Fe by $3$ on left and to make $O 4$ multiply $\ce{H_2O}$ by $4$
$\therefore \ce{3Fe} +\ce{4H2O \rightleftharpoons Fe_3O_4}+\ce{4H_2}$

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