Based on solute-solvent interactions, arrange the following in order of increasing solubility in n-octane and explain.
Cyclohexane, $\mathrm{KCl}, \mathrm{CH}_3 \mathrm{OH}, \mathrm{CH}_3 \mathrm{CN}$.
Cyclohexane, $\mathrm{KCl}, \mathrm{CH}_3 \mathrm{OH}, \mathrm{CH}_3 \mathrm{CN}$.
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n-octane is non-polar solvent therefore the solubility of a non-polar solute is more in n-octane solvent.
The order of increasing solubility is:
$\mathrm{KCl} < \mathrm{CH}_3 \mathrm{OH} < \mathrm{CH}_3 \mathrm{CN} < $ cyclohexane.
The order of increasing solubility is:
$\mathrm{KCl} < \mathrm{CH}_3 \mathrm{OH} < \mathrm{CH}_3 \mathrm{CN} < $ cyclohexane.
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