Question
$\mathrm{BCl}_3$ exists but $\mathrm{BH}_3$ does not. Explain.

Answer

In $\mathrm{BCl}_3, \mathrm{Cl}$ donates lone pair of electrons to vacant p-orbital of boron (back-bonding) making it more stable whereas in $\mathrm{BH}_3$ back-bonding is not possible, therefore, it exists as dimer. Secondly, in $\mathrm{BCl}_3$, chlorine being bigger in size cannot form bridged bonds like hydrogen in $\mathrm{B}_2 \mathrm{H}_6$.

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