Question
$\begin{bmatrix}2&3\\5&7\end{bmatrix}\begin{bmatrix}1&-3\\-2&4\end{bmatrix}=\begin{bmatrix}-4&6\\-9&\text{x}\end{bmatrix}$ find x.

Answer

Given: $\begin{bmatrix}2&3\\5&7\end{bmatrix}\begin{bmatrix}1&-3\\-2&4\end{bmatrix}=\begin{bmatrix}-4&6\\-9&\text{x}\end{bmatrix}$
$\Rightarrow\begin{bmatrix}2-6&-6+12\\5-14&-15+28\end{bmatrix}=\begin{bmatrix}-4&6\\-9&\text{x} \end{bmatrix}$
$\Rightarrow\begin{bmatrix}-4&6\\-9&\text{x} \end{bmatrix}=\begin{bmatrix}-4&6\\-9&\text{x} \end{bmatrix}$
$\Rightarrow\text{x}=3$
$\therefore\ \text{x}=13$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions