MCQ
$\begin{array}{*{20}{c}}
  {C{l_3}\mathop C\limits^3  - \mathop C\limits^2 H = \mathop C\limits^1 {H_2}} \\ 
  {(I)} 
\end{array}\,\,\,\,\,\,\,\,\,\,\,\,\,\begin{array}{*{20}{c}}
  {{H_3}\mathop C\limits^3  - \mathop C\limits^2 H = \mathop C\limits^1 {H_2}} \\ 
  {(II)} 
\end{array}$

In addition of $HOBr$ to $(I)$ and $(II)$

  • A
    $Br$ is at $C_2$ in both cases
  • B
    $Br$ is at $C_2$ in $II$ and at $C_1$ in $I$
  • $Br$ is at $C_1$ in $II$ and $C_2$ in $I$
  • D
    $Br$ is at $C_1$ in both cases

Answer

Correct option: C.
$Br$ is at $C_1$ in $II$ and $C_2$ in $I$
c

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