2x&5 8&x = 6x&-2 7&3 , then the value of x is: - Vidyadip

MCQ

$\begin{bmatrix}2\text{x}&5\\8&\text{x}\end{bmatrix}=\begin{bmatrix}6\text{x}&-2\\7&3\end{bmatrix},$ then the value of $\text{x}$ is:

A
$3$
B
$\pm3$
✓
$\pm6$
D
$6$

✓

Answer

Correct option: C.

$\pm6$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from DETERMINANTS→DETERMINANTS — all question types→Maths STD 12 Science question papers→Gujarat Board STD 12 Science question papers→Gujarat Board question paper generator→

Similar questions

If ${\cos ^{ - 1}}p + {\cos ^{ - 1}}q + {\cos ^{ - 1}}r = \pi $ then ${p^2} + {q^2} + {r^2} + 2pqr = $

Evaluate$:\ \int\sqrt{1+\text{y}}^2.\text{2ydy:}$

Choose the correct answer from the given four options: The function $f(x) = 2x^3 - 3x^2 - 12x + 4,$ has:

Let the locus of the centre $(\alpha, \beta), \beta>0$, of the circle which touches the circle $x ^{2}+( y -1)^{2}=1$ externally and also touches the $x$-axis be $L$. Then the area bounded by $L$ and the line $y =4$ is.

If $\int\limits^\alpha_0\frac{1}{1+4\text{x}^2}\text{ dx}=\frac{\pi}{8},$ then a equals:

If $\text{A}= \begin{bmatrix} 1 &\text{amp; } 2 &\text{amp;} 3\end{bmatrix},$ then order is :

The foot of perpendicular of the point $(2,0,5)$ on the line $\frac{x+1}{2}=\frac{y-1}{5}=\frac{z+1}{-1}$ is $(\alpha, \beta, \gamma)$. Then. Which of the following is $NOT$ correct?

$\int\frac{2\text{dx}}{\sqrt{1-4\text{x}^2}}=$

If $u = {({x^2} + {y^2} + {z^2})^{3/2}}$, then ${\left( {{{\partial u} \over {\partial x}}} \right)^2} + {\left( {{{\partial u} \over {\partial y}}} \right)^2} + {\left( {{{\partial u} \over {\partial z}}} \right)^2} = $

The point on the curve $y ^2= x$ where tangent makes $45^{\circ}$ angle with $x -$ axis is :