MCQ
$\begin{matrix}
   \,\,\,Br\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,Br\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
   \,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,  \\
   C{{H}_{2}}-CH=CH-C{{H}_{2}}\xrightarrow{Zn\,(dust)}(A)  \\
\end{matrix}$

Above reaction is an example of $1,4$ -elimination. Predict the product.

  • A
    $CH_3 - CH = C = CH_2$
  • B
    $CH_3 - C \equiv C - CH_3$
  • C
    $CH_3 - CH_2 - C \equiv CH$
  • $H_2C = CH - CH = CH_2$

Answer

Correct option: D.
$H_2C = CH - CH = CH_2$
d

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