MCQ
Benedict solution provides
- A$A{g^ + }$
- B$L{i^ + }$
- ✓$C{u^{ + 2}}$
- D$B{a^{ + 2}}$
✓
Answer
Correct option: C.
$C{u^{ + 2}}$
c
Benedict's solution is used to test for reducing sugars (free aldehyde group). The aldehyde gets oxidised and in the process, reduces the $Cu ^{+}$found in the complex provided by Benedict solution to form copper$(I)$ oxide, $Cu _2 O$.
Benedict's solution is used to test for reducing sugars (free aldehyde group). The aldehyde gets oxidised and in the process, reduces the $Cu ^{+}$found in the complex provided by Benedict solution to form copper$(I)$ oxide, $Cu _2 O$.
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Similar questions
Of the different allotropes of phosphorus, the one which is most reactive is
$\begin{array}{*{20}{c}}
{C{H_3} - C - C{H_2} - C - O - C{H_3}} \\
\,\,{||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$ $\xrightarrow[{{H^ \oplus }}]{{{H_2}O}}A\xrightarrow{\Delta }B\xrightarrow{{HCN}}C$
→{C{H_3} - C - C{H_2} - C - O - C{H_3}} \\
\,\,{||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$ $\xrightarrow[{{H^ \oplus }}]{{{H_2}O}}A\xrightarrow{\Delta }B\xrightarrow{{HCN}}C$
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