MCQ
Benzene shows
- ASubstitution
- BAddition
- COxidation
- ✓All of these
Benzene resists addition reactions because that would involve breaking the delocalisation and losing that stability.
An alkylbenzene is simply a benzene ring with an alkyl group attached to it. ... Alkyl groups are usually fairly resistant to oxidation. However, when they are attached to a benzene ring, they are easily oxidised by an alkaline solution of potassium manganate($VII$) (potassium permanganate).
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$I.$ ${C_2}{H_4}$ $II.$ ${C_2}{H_2}$
$III.$ ${C_6}{H_6}$ $IV.$ ${C_2}{H_6}$
$\begin{array}{|l|l|} \hline List\,\,I & List\,\,II \\ \hline (A)\,\,Peroxide & (1)\,\,{C_3}{O_2} \\ \hline (B)\,\,Superoxide & (2)\,\,Pb{O_2} \\ \hline (C)\,\,Dioxide & (3)\,\,K{O_2} \\ \hline (D)\,\,Suboxide & (4)\,\,{H_2}{O_2} \\ \hline \end{array}$
Statement $I$: The boiling point of hydrides of Group $16$ elements follow the order
$\mathrm{H}_2 \mathrm{O}>\mathrm{H}_2 \mathrm{Te}>\mathrm{H}_2 \mathrm{Se}>\mathrm{H}_2 \mathrm{~S}$.
Statement $II$: On the basis of molecular mass, $\mathrm{H}_2 \mathrm{O}$ is expected to have lower boiling point than the othe members of the group but due to the presence of extensive $\mathrm{H}$-bonding in $\mathrm{H}_2 \mathrm{O}$, it has higher boiling point.
In the light of the above statements, choose the correct answer from the options given below: