MCQ
Benzoyl chloride is prepared from benzoic acid by
- A$C{l_2},\,\,hv$
- B$S{O_2}C{l_2}$
- ✓$SOC{l_2}$
- D$C{l_2},{H_2}O$

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$\begin{array}{*{20}{c}}
{C{H_3}CH = C{H_2} + {H_2}O\overset {{H^ + }} \longleftrightarrow C{H_3} - CH - C{H_3}} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,OH}
\end{array}$
The reaction takes place in accordance with