MCQ
$\Big(\frac{-1}{2}\Big)^5\times\Big(\frac{-1}{2}\Big)^3$ is equal to:
- ✓$\Big(\frac{-1}{2}\Big)^{8}$
- B$-\Big(\frac{1}{2}\Big)^8$
- C$\Big(\frac{1}{4}\Big)^8$
- D$\Big(-\frac{1}{2}\Big)^{15}$
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