MCQ
$\Big(\frac{-1}{3}\Big)^3\div\Big(\frac{-1}{5}\Big)^8$ is equal to:
  • A
    $\Big(\frac{-1}{5}\Big)^{5}$
  • B
    $\Big(-\frac{1}{5}\Big)^{11}$
  • $(-5)^5 $
  • D
    $\Big(\frac{1}{5}\Big)^{5}$

Answer

Correct option: C.
$(-5)^5 $
We have:
$\Big(\frac{-1}{5}\Big)^3\div\Big(\frac{-1}{5}\Big)^8$
$=\Big(\frac{-1}{5}\Big)^{3-8}$
$=\Big(\frac{-1}{5}\Big)^{-5}$
$=\frac{1}{\big(\frac{-1}{5}\big)^5}$
$=\frac{1}{\big(\frac{(-1)^5}{5^5}\big)}$
$=\frac{5^5}{(-1)^5}$
$=\Big(\frac{5}{-1}\Big )^5$
$=(-5)^5$

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