MCQ
$\Big(\frac{-1}{3}\Big)^3\div\Big(\frac{-1}{5}\Big)^8$ is equal to:
- A$\Big(\frac{-1}{5}\Big)^{5}$
- B$\Big(-\frac{1}{5}\Big)^{11}$
- ✓$(-5)^5 $
- D$\Big(\frac{1}{5}\Big)^{5}$
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