MCQ
$\Big(\frac{-2}{5}\Big)^7\div\Big(\frac{-2}{5}\Big)^5$ is equal to:
  • $\frac{4}{25}$
  • B
    $\frac{-4}{25}$
  • C
    $\Big(\frac{-2}{5}\Big)^{12}$
  • D
    $\frac{25}{4}$

Answer

Correct option: A.
$\frac{4}{25}$
We have:
$\Big(\frac{-2}{5}\Big)^7\div\Big(\frac{-2}{5}\Big)^5=\Big(\frac{-2}{5}\Big)^{7-5}$
$=\Big(\frac{-2}{5}\Big)^{2}$
$=\frac{(-2)^2}{5^2}$
$=\frac{4}{25}$

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