Question
$\Big(-5\times\frac{2}{15}\Big)-\Big(-6\times\frac{2}{9}\Big)$

Answer

$\Big(-5\times\frac{2}{15}\Big)-\Big(-6\times\frac{2}{9}\Big)$
$=\frac{-5\times2}{15}-\Big(\frac{-6\times2}{9}\Big)$
$=\frac{-1\times2}{3}-\frac{-2\times2}{3}=\frac{-2}{3}-\frac{-4}{3}$
$=\frac{-2+4}{3}=\frac{2}{3}$

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