Question
$\Big(\frac{13}{14}\Big)^{5}\div(\ )^{2}=\Big(\frac{13}{14}\Big)^{3}$
Solution:
Let
$\Big(\frac{13}{14}\Big)^{5}\div(\text{x})^{2}=\Big(\frac{13}{14}\Big)^{3}$ $\therefore(\text{x})^{2}=\frac{\Big(\frac{13}{14}^{5}\Big)}{\Big(\frac{13}{14}\Big)^{3}}$ $\therefore(\text{x})^{2}=\Big(\frac{13}{14}\Big)^{5-3}$ $\big[\because\frac{\text{a}^{\text{m}}}{\text{a}^{\text{n}}}=\text{a}^{\text{m-n}}\big]$ $\therefore(\text{x})^{2}=\Big(\frac{13}{14}\Big)^{2}$ Since, powers are same. $\therefore\text{x}=\frac{13}{14}$ Hence, $\Big(\frac{13}{14}\Big)^{5}\div(\text{x})^{2}=\Big(\frac{13}{14}\Big)^{3}$Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.