MCQ
$\big(\frac{1}{3}\big)^2$ is equal to:
- A$9$
- B$-9$
- C$\frac{-1}{9}$
- ✓$\frac{1}{9}$
✓
Answer
Correct option: D.
$\frac{1}{9}$
$\big(\frac{1}{3}\big)^2 = \big(\frac{1}{3}\times\frac{1}{3}\big) = \frac{1}{9}$
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