MCQ
$\Big(\frac{2}{3}\Big)^{-5}$ is equal to:
  • A
    $\Big(\frac{-2}{3}\Big)^5$
  • $\Big(\frac{3}{2}\Big)^5$
  • C
    $\frac{2\text{x}-5}{3}$
  • D
    $\frac{2}{3\times5}$

Answer

Correct option: B.
$\Big(\frac{3}{2}\Big)^5$
Rearrange $\Big(\frac{2}{3}\Big)^{-5}$ to get a positive exponent.
$\Big(\frac{2}{3}\Big) ^{-5}=\frac{1}{\big(\frac{2}{3}\big)^5}$
$=\frac{1}{2^5}$
$=\frac{\frac{3^5}{2^5}}{3^5}$
$=\frac{3^5}{2^5}$
$=\Big (\frac{3}{2}\Big)^5$

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