MCQ
$\Big(\frac{2}{3}\Big)^{-5}\times\Big(\frac{5}{7}\Big)^{-5}$ is equal to:
  • A
    $\Big(\frac{2}{3}\times\frac{5}{7}\Big)^{-10}$
  • $\Big(\frac{2}{3}\times\frac{5}{7}\Big )^{-5}$
  • C
    $\Big(\frac{2}{3}\times\frac{5}{7}\Big)^{25}$
  • D
    $\Big(\frac{2}{3}\times\frac{5}{7}\Big)^{-25}$

Answer

Correct option: B.
$\Big(\frac{2}{3}\times\frac{5}{7}\Big )^{-5}$
We have:
$\Big(\frac{2}{3}\Big)^{-5}\times\Big(\frac{5}{7}\Big)^{-5}=\Big(\frac{2}{3}\times\frac{5}{7}\Big)^{-5}$

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