MCQ
$\big(\frac{2}{3}\big)^{3}\times\big(\frac{5}{7}\big)^{3}$ is equal to:
  • A
    $\big(\frac{2}{3}\times\frac{5}{7}\big)^{9}$
  • B
    $\big(\frac{2}{3}\times\frac{5}{7}\big)^{6}$
  • $\big(\frac{2}{3}\times\frac{5}{7}\big)^{3}$
  • D
    $\big(\frac{2}{3}\times\frac{5}{7}\big)^{9}$

Answer

Correct option: C.
$\big(\frac{2}{3}\times\frac{5}{7}\big)^{3}$

We know that, if $a$, $b$ and $m$ are rational numbers, then
$\text{a}^{\text{m}}\times\text{b}^{\text{m}}=\text{ab}^{\text{m}}$
So, $\big(\frac{2}{3}\big)^{3}\times\big(\frac{5}{7}\big)^{3}=\big(\frac{2}{3}\times\frac{5}{7}\big)^{3}$

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