Question
$\Big(\frac{5}{8}\Big)^{9}\div\Big(\frac{5}{8}\Big)^{4}=\Big(\frac{5}{8}\Big)^{4}$
✓
Answer
False. Solution: Here,$\Big(\frac{5}{8}\Big)^{9}\div\Big(\frac{5}{8}\Big)^{4}=\Big(\frac{5}{8}\Big)^{9-4}=\Big(\frac{5}{8}\Big)^{5}$ $\big[\because\text{a}^{\text{m}}+\text{a}^{\text{m}}=\text{a}^{\text{m-n}}\big]$ Hence, $\Big(\frac{5}{8}\Big)^{9}\div\Big(\frac{5}{8}\Big)^{4}\neq\Big(\frac{5}{8}\Big)^{4}$
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