Question
$\Bigg[\Big(\frac{7}{11}\Big)^{3}\Bigg]^{4}=\Big(\frac{7}{11}\Big)$
✓
Answer
$\Bigg[\Big(\frac{7}{11}\Big)^{3}\Bigg]^{4}=\Big(\frac{7}{11}\Big)^{3\times4}$ Solution: Here, $\Bigg[\Big(\frac{7}{11}\Big)^{3}\Bigg]^{4}=\Big(\frac{7}{11}\Big)^{3\times4}=\Big(\frac{7}{11}\Big)^{12}$ $\big[\because(\text{a}^{\text{m}})^{\text{n}}=\text{a}^{\text{mn}}\big]$ $\therefore\bigg[\Big(\frac{7}{11}\Big)^{3}\bigg]=\Big(\frac{7}{11}\Big)^{12}$
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