Question
$\big(\vec{\text{a}}+\vec{\text{b}}\big).\big(\vec{\text{b}}+\vec{\text{c}}\big)\times\big(\vec{\text{a}}+\vec{\text{b}}+\vec{\text{c}}\big)=$
  1. $0$
  2. $-\big[\vec{\text{a}}\vec{\text{b}}\vec{\text{c}}\big]$
  3. $2\big[\vec{\text{a}}\vec{\text{b}}\vec{\text{c}}\big]$
  4. $\big[\vec{\text{a}}\vec{\text{b}}\vec{\text{c}}\big]$

Answer

  1. $\big[\vec{\text{a}}\vec{\text{b}}\vec{\text{c}}\big]$
Solution:
We have
$\big(\vec{\text{a}}+\vec{\text{b}}\big).\big(\vec{\text{b}}+\vec{\text{c}}\big)\times\big(\vec{\text{a}}+\vec{\text{b}}+\vec{\text{c}}\big)$
$=\big(\vec{\text{a}}+\vec{\text{b}}.\big[\big(\vec{\text{b}}+\vec{\text{c}}\big)\times\vec{\text{a}}+\big(\vec{\text{b}}+\vec{\text{c}}\big)\times\vec{\text{b}}+\big(\vec{\text{b}}+\vec{\text{c}}\big)\times\vec{\text{c}}\big]$
$=\big(\vec{\text{a}}+\vec{\text{b}}\big).\big(\vec{\text{b}}\times\vec{\text{a}}+\vec{\text{c}}\times\vec{\text{a}}+\vec{\text{b}}\times\vec{\text{b}}+\vec{\text{c}}\times\vec{\text{b}}+\vec{\text{b}}\times\vec{\text{c}}+\vec{\text{c}}\times\vec{\text{c}}\big)$
$=\big(\vec{\text{a}}+\vec{\text{b}}\big).\big(\vec{\text{b}}\times\vec{\text{a}}+\vec{\text{c}}\times\vec{\text{a}}+0+\vec{\text{c}}\times\vec{\text{b}}+\vec{\text{b}}\times\vec{\text{c}}+0$
$=\big(\vec{\text{a}}+\vec{\text{b}}\big).\big(\vec{\text{b}}\times\vec{\text{a}}+\vec{\text{c}}\times\vec{\text{a}}-\vec{\text{b}}\times\vec{\text{c}}+\vec{\text{b}}\times\vec{\text{c}}\big)$
$=\big(\vec{\text{a}}+\vec{\text{b}}\big).\big(\vec{\text{b}}\times\vec{\text{a}}+\vec{\text{c}}\times\vec{\text{a}}\big)$
$=\vec{\text{a}}\big(\vec{\text{b}}\times\vec{\text{a}}\big)+\vec{\text{b}}.\big(\vec{\text{b}}\times\vec{\text{a}}\big)+\vec{\text{a}}.\big(\vec{\text{c}}\times\vec{\text{a}}\big)+\vec{\text{b}}.\big(\vec{\text{c}}\times\vec{\text{a}}\big)$
$=0+0+0+\big[\vec{\text{b}}\vec{\text{c}}\vec{\text{a}}\big]$
$=\big[\vec{\text{b}}\vec{\text{c}}\vec{\text{a}}\big]$
$=\big[\vec{\text{a}}\vec{\text{b}}\vec{\text{c}}\big]$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

A speaks truth in 75% cases and B seaks truth in 80% cases. Probability that they contradict each other in a statement, is
  1. $\frac{7}{20}$
  2. $\frac{13}{20}$
  3. $\frac{3}{5}$
  4. $\frac{2}{5}$
Maximize $Z = 10 x_1 + 25 x_2,$ subject to $0\leq\text{x}_{1}\leq3,0\leq\text{x}_{2}\leq3,\text{x}_{1}+\text{x}_{2}\leq5.$
If the points $(p, 0), (0, q)$ and $(1, 1)$ are collinear, then $\frac{1}{\text{p}}+\frac{1}{\text{q}}$​ is equal to:
If $\tan^{-1}\Big(\frac{\text{a}}{\text{x}}\Big)+\tan^{-1}\Big(\frac{\text{b}}{\text{x}}\Big)=\frac{\pi}{2},$ then x is equal to:
  1. $\sqrt{\text{ab}}$
  2. $\sqrt{2\text{ab}}$
  3. $2\text{ab}$
  4. $\text{ab}$
The area bounded by the curve y = f(x), above the x - axis, between ax = a and x = b is:
  1. $\int\limits^{\text{b}}_{\text{f(a)}}\text{ydy}$
  2. $\int\limits^{\text{fb}}_{\text{(b)}}\text{xdx}$
  3. $\int\limits^{\text{b}}_{\text{a}}\text{xdy}$
  4. $\int\limits^{\text{b}}_{\text{a}}\text{ydx}$
The function $\text{f(x)}=\frac{\sin(\text{x}|\text{x}-\pi|)}{4+|\text{x}|^2},$ where[.] denotes the greatest integer function, is:
  1. Continuous as well as differentiable for all $\text{x}\in\text{R}$
  2. Continuous for all x but differentiable at some x
  3. Differentiable for all x but not continuous at some x
  4. None of these.
$(\vec{a} \cdot \hat{i})^2+(\vec{a} \cdot \hat{j})^2+(\vec{a} \cdot \hat{k})^2$ is equal to
If $\sin^{-1}\text{x}-\cos^{-1}\text{x}=\frac{\pi}{6},$ then x =
  1. $\frac{1}{2}$
  2. $\frac{\sqrt{3}}{2}$
  3. $-\frac{1}{2}$
  4. $-\frac{\sqrt{3}}{2}$
An operation * is defined on the set Z of non-zero integers by a * b = ab for all a, b ∈ Z. Then the property satisfied is:
  1. Closure.
  2. Commutative.
  3. Associative.
  4. None of these.
If $\text{f}(\text{x})=(\cos\text{x}+\text{i}\sin\text{x})(\cos2\text{x}+\text{i}\sin2\text{x})(\cos3\text{x}+\text{i}\sin3\text{x})...(\cos\text{nx}+\text{i}\sin\text{nx})\ \text{and}\ \text{f}(1)=1, $ then f1 is equals to:
  1. $$$\frac{\text{n}(\text{n}+1)}{2}$
  2. $\Big\{\frac{\text{n}(\text{n}+1)}{2}\Big\}^2$
  3. $-\Big\{\frac{\text{n}(\text{n}+1)}{2}\Big\}^2$
  4. $\text{none of these}$