MCQ
Bleaching action of $S{O_2}$ is due to
- ✓Reduction
- BOxidation
- CHydrolysis
- DIts acidic nature
Coloured flower $ + \,2[H] \to $Colourless flower
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(Atomic no. : $B = 5,S = 16,Ni = 28,Xe = 54$)
(Molar mass of $\mathrm{H}_3 \mathrm{PO}_4=98 \mathrm{~g} \mathrm{~mol}^{-1}$ )

