MCQ
Blue vitriol is
- A$CuS{O_4}$
- ✓$CuS{O_4}.5{H_2}O$
- C$C{u_2}S{O_4}$
- D$CuS{O_4}.{H_2}O$
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$E _{ FeO _4^{2-} / Fe ^{2+}}^\theta$ is $x \times 10^{-3} V$. The value of $x$ is $.........$.
$(I)\, (CH_3)_2P(CF_3)_3$ is non-polar and $(CH_3)_3P(CF_3)_2$ is polar molecule
$(II)\, CH_3 \widehat{P} CH_3$ bond angles are equal in $(CH_3)_3P(CF_3)_2$ molecule
$(III)\,PF_3$ will be more soluble in polar solvent than $SiF_4$