MCQ
Bohr's model can explain
- AThe spectrum of hydrogen atom only
- ✓Spectrum of atom or ion containing one electron only
- CThe spectrum of hydrogen molecule
- DThe solar spectrum
✓
Answer
Correct option: B.
Spectrum of atom or ion containing one electron only
b
(b) According to the Bohr model atoms or ions contain one electron.
(b) According to the Bohr model atoms or ions contain one electron.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
As compared to pure atomic orbitals, hybrid orbitals have
Compound $X$ on reaction with $O _{3}$ followed by $Zn /$ $H _{2} O$ gives formaldehyde and $2-$methyl propanal as products. The compound $X$ is :
→The first order rate constant for the decomposition of $\mathrm{CaCO}_{3}$ at $700\, \mathrm{~K}$ is $6.36 \times 10^{-3}\, \mathrm{~s}^{-1}$ and activation energy is $209\, \mathrm{~kJ} \,\mathrm{~mol}^{-1}$. Its rate constant (in $\mathrm{s}^{-1}$ ) at $500\, \mathrm{~K}$ is $\mathrm{x} \times 10^{-6}$. The value of $\mathrm{x}$ is ..... . Nearest integer)
→Given $\mathrm{R}=8.31\, \mathrm{~J} \,\mathrm{~K}^{-1} \,\mathrm{~mol}^{-1} ; \log 6.36 \times 10^{-3}=-2.19$ $\left.10^{-4.79}=1.62 \times 10^{-5}\right]$
A solution of sulphur dioxide in water reacts with ${H_2}S$ precipitating sulphur. Here sulphur dioxide acts as
→Incorrect statement for the use of indicators in acid-base titration is :
The major product of the following reaction is
→$\begin{array}{*{20}{c}}
{C{H_3}\,\,\,} \\
{|\,\,\,\,\,\,\,\,} \\
{C{H_3} - C - CHC{H_3}} \\
{\,|\,\,\,\,\,\,\,\,\,\,|} \\
{\,\,H\,\,\,\,\,\,\,Br}
\end{array}$ $\xrightarrow{{C{H_3}OH}}$
Which statement is not correct for nitrogen
Metal-metal bonding is more frequent in $4d$ or $5d$ series than in $3d$ series due to
→Predict the product when given compound reacts with $LiAlH_4$
→A gaseous mixture contains $CH_4$ and $C_2H_6$ in equimolecular proportion. The weight of $2.24\,litres$ of this mixture at $NTP$ is .............. $\mathrm{g}$
→